Using proportions, it is found that:
a) The value of the destroyed part of the inventory is of $56,000.
b) The value of the inventory before the fire was of $77,000.
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, 8/11 of his inventory was destroyed, hence 3/11 remained. The amount that remained was sold for 1/6 of it's value, and he received $3500, hence the value before the fire was given by:
[tex]\frac{1}{6}\left(\frac{3}{11}\right)n = 3500[/tex]
[tex]\frac{1}{22}n = 3500[/tex]
n = $77,000.
8/11 of that was destroyed, hence:
vD = 8/11 x $77,000 = 8 x $7,000 = $56,000.
More can be learned about proportions at https://brainly.com/question/24372153
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