Respuesta :

[tex]\\ \rm\Rrightarrow \dfrac{2}{x+3}-\dfrac{1}{x-3}=\dfrac{-7}{x^2-9}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{2(x-3)-1(x+3)}{(x+3)(x-3)}=\dfrac{-7}{x^2-9}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{2x-6-x-3}{x^2-9}=\dfrac{-7}{x^2-9}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x-9}{x^2-9}=\dfrac{-7}{x^2-9}[/tex]

[tex]\\ \rm\Rrightarrow x-9=-7[/tex]

[tex]\\ \rm\Rrightarrow x=9-7[/tex]

[tex]\\ \rm\Rrightarrow x=2[/tex]

semsee45

Answer:

x = 2

Step-by-step explanation:

[tex]\large \begin{aligned}\dfrac{2}{x+3}-\dfrac{1}{x-3} & = \dfrac{-7}{x^2-9}\\\\\dfrac{2(x-3)}{(x+3)(x-3)}-\dfrac{1(x+3)}{(x+3)(x-3)} & = \dfrac{-7}{(x+3)(x-3)}\\\\\dfrac{2(x-3)-(x+3)}{(x+3)(x-3)} & = \dfrac{-7}{(x+3)(x-3)}\\\\\dfrac{x-9}{(x+3)(x-3)} & = \dfrac{-7}{(x+3)(x-3)}\\\\x-9 & = -7\\\\x&=-7+9\\\\x & = 2\end{aligned}[/tex]

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