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URGENT PLEASE!
A 0.02kg ball was hit giving it a velocity of 25. What impulse force did it impart on the ball? Use the impulse-momentum theorem to derive your answer. (I = FΔt) and (p = m Δv )

Please show your solution and drawing! I would really appreciate it!

Respuesta :

nuhulawal20

Given the mass and change in velocity of the ball, the impulse force imparted on the ball is 0.5kgm/s.

What is impulse?

An impulse is simply a concept that involves the change in the momentum of an object when force is introduced for a period of time.

Using the formula of impulse.

ΔP or Change in Momentum  = Ft  = m( v - u )

Where m is mass, v is final velocity and u is initial velocity

Given that;

  • Mass of the ball m = 0.02kg
  • Initial velocity (before it was hit) u = 0
  • Final velocity ( after it was hit ) v = 25m/s
  • Impulse force ΔP  = ?

ΔP = m( v - u )

ΔP =  0.02kg( 25m/s - 0 )

ΔP =  0.02kg( 25m/s )

ΔP =  0.5kgm/s

Given the mass and change in velocity of the ball, the impulse force imparted on the ball is 0.5kgm/s.

Learn more about impulse here: brainly.com/question/26877615

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