The block with the bullet after collision lodged in it is now travelling at 2.133 m/s.
When there is no external force acting on the system , the initial momentum is equal to final momentum.
The momentum is the product of mass and its velocity.
Given is the mass of bullet m₁ = 0.1 kg, mass of block m₂ =14.9kg, velocity of bullet before collision u₁ =320 m/s, velocity of block before collision u₂ =0. The final velocity of block and bullet both is v.
According to the momentum conservation principle,
m₁u₁ +m₂u₂ = (m₁ +m₂) v
Substitute the values into the expression to find the final velocity,
0.1 x 320 +14.9 x 0 =(0.1 +14.9) v
v = 2.133 m/s
Thus, the block with the bullet logged in it is moving at 2.133 m/s.
Learn more about conservation of momentum principle.
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