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Hailey loves to hang out at the bowling alley! With one pin still standing, she rolls a 6-kg bowling ball down the lane hitting the pin head on with a speed of 5 m/s. The 1.5-kg pin acquires a forward velocity of 12 m/s. How fast is the bowling ball travelling after the collision?

Velocity: _ m/s

Respuesta :

The bowling ball travelling after the collision will be 9.125 m/sec.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

[tex]\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\ 6\ kg \times 15 \ m/sec+1.5 \ kg \times 5 \ m/sec = (6+15)\times V\\\\\ V=\frac{ 90+7.5}{12}\\\\ V=9.125 \ m/sec[/tex]

Hence, the bowling ball travelling after the collision will be 9.125 m/sec.

To learn more about the law of conservation of momentum, refer;

https://brainly.com/question/1113396

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