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From his eye, which stands 1.63 meters above the ground, Isaac measures the angle
of elevation to the top of a prominent skyscraper to be 17°. If he is standing at a
horizontal distance of 294 meters from the base of the skyscraper, what is the height
of the skyscraper? Round your answer to the nearest hundredth of a meter if
necessary.

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The height of the skyscraper if the angle of elevation to the top of a prominent skyscraper to be 17° is 91.51 meter

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let h represent the height of the skyscraper, hence:

tan(17) = h/294

h = 89.88 meter

Total height = 89.88 + 1.63 = 91.51 meter

The height of the skyscraper if the angle of elevation to the top of a prominent skyscraper to be 17° is 91.51 meter

Find out more on equation at: https://brainly.com/question/2972832

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