[tex]\huge{\green}\fcolorbox{blue}{black}{\bf{\underline{\red{\color{brown}Answer}}}}[/tex]
4.44l
Explanation:
[tex] \sf Volume \: of \: gas \: before(V_1) = 2.7 \: l \\ \sf Pressure \: of \: gas \: before(P_1) = 0.63 \: atm \\ \sf 0.63 \times 101.3 = 63.8 \: kPa \\ \sf Volume \: of \: gas \: after(V_2) = ? \\ \sf Pressure \: of \: gas \: after( P_2) = 105 \: kPa[/tex]
[tex] \textsf{ By using Boyle's law} \\ \\ \tt{ \frac{P_1}{V_1} = \frac{P_2}{V_2} }[/tex]
[tex] \sf \longrightarrow \frac{2.70}{63.8} = \frac{V_2}{105} \\ \\ \\ \sf \longrightarrow \frac{2.7 \times 105}{63.8} = V_2 \\ \\ \\ \sf \longrightarrow \frac{283.5}{63.8} = V_2 \\ \\ \\ {\orange {\boxed{ \longrightarrow 4.44 \: l = V_2}}}[/tex]
