Bryn has a stack of photos measuring 12cm wide and 16cm high. He wants to display them on a large rectangular poster in such a way that all photos are equally spaced on each side, including at the edges of the poster, as illustrated.

1.. Bryn wants to display 9 photos (with longer side vertical) in 3 rows of 3 photos each with 2cm spacing around each photo. What are the dimensions of the poster?

2. Bryn wants to display 24 photos (with longer side vertical) with 2cm spacing around each photo. He wants more columns than rows of photos. Find the smallest poster area that is needed.

3. Bryn wants to display 18 photos in 3 rows of 6 photos each with 3cm spacing around each photo. The photos may all be displayed in portrait orientation (longer side vertical) or in landscape (longer side horizontal). Which orientation uses the lesser poster area?

4. Bryn wants to display 24 photos (with longer side vertical) in 6 rows of 4 photos each with equal spacing around each photo. He has a poster that is 62 cm wide and 120cm high. He wants to use the full width of the poster but is prepared to trim some of its height to achieve the equal spacing. How much of the poster does he need to trim?

Please provide working out for all the questions. Thanks.

Bryn has a stack of photos measuring 12cm wide and 16cm high He wants to display them on a large rectangular poster in such a way that all photos are equally sp class=

Respuesta :

The width of the poster is 44 cm, and the length of the poster is 56 cm.

What is the area of the rectangle?

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

Bryn has a stack of photos measuring 12 cm wide and 16 cm high.

1) Bryn wants to display 9 photos (with longer side vertical) in 3 rows of 3 photos each with 2 cm spacing around each photo.

The total width of the poster = 12×3 + 8 = 36 + 8 = 44 cm

The total length of the poster = 16×3 + 8 = 48 + 8 = 56 cm

Similarly, we can find the dimensions of the poster and further find the area of the rectangle by using the formula:

Rectangle area = length x width

Thus, the width of the poster is 44 cm, and the length of the poster is 56 cm.

Learn more about the rectangle here:

https://brainly.com/question/15019502

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