Answer:
E
Explanation:
The empirical formula has a mass of
3*C = 3*12 = 36
4*H = 4*1 = 4
1*O = 1 * 16 = 16 Add
Total = 56
The actual mass of the molecule in nature is 112
Multiplier = nature's mass / empirical formula mass
Values
Nature's mass = 112
Empirical mass = 56
Solution
Multiplier = Natures mass/Empirical Mass
Multiplier = 112 / 56
Multiplier = 2
Formula
Nature's formula = (Emperical Mass)_multiplier
Nature's formula = (C3H4O)_2 Multiply
Nature's formula = C6H8O2
Check
C6 = 6*C = 6*12 = 72
H8 = 8*H = 8*1 = 8
O2 = 2*O = 2*16 = 32 Add
Total 112 which checks with what is given.
