There are two squares. the perimeter of square x is half the perimeter of square y.
how do the areas of the two squares compare?
o a. the area of square x is one-sixteenth the area of square y.
o b. the area of square x is one-eighth the area of square y.
oc. the area of square x is one-fourth the area of square y.
d. the area of square x is one-half the area of square y.

It is a polygon with four sides. The total interior angle is 360 degrees. A square's opposite sides are parallel and all sides are equal, and each angle is 90 degrees. Its diagonals are all the same length and intersect in the center.

There are two squares.

The perimeter of square x is half the perimeter of square y.

Let the side of the square x be a and the side length of the square y be b. Then we have

Perimeter x = Perimeter y / 2

4a = 2b

2a = b

Then the area of the square x will be

Area of square x = (2a)²

Area of square x = 4a²

Then the area of the square y will be

Area of square x = (b)²

Area of square x = b²

Then the area of square x will be one-fourth of the area of square y.

Thus, the correct option is C.

More about the square link is given below.

https://brainly.com/question/13747846

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