the function f(x)= -x3 - 7x2 - 7x + 15 has zeros located at -5, -3, 1. verify the zeros of f(x) and explain how you verified them. describe the end behavior of the
function

Respuesta :

The polynomial f(x)= -x³ - 7x² - 7x + 15 has zeros located at -5, -3, 1 because f(-5) = f(-3) = f(1) = 0

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The function f(x)= -x³ - 7x² - 7x + 15 has zeros located at -5, -3, 1, hence:

f(-5) = -(-5)³ - 7(-5)² - 7(-5) + 15 = 0

f(-3) = -(-3)³ - 7(-3)² - 7(-3) + 15 = 0

f(1) = -(1)³ - 7(1)² - 7(1) + 15 = 0

The polynomial f(x)= -x³ - 7x² - 7x + 15 has zeros located at -5, -3, 1 because f(-5) = f(-3) = f(1) = 0

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