You cut the 2 inch by 4 inch piece of wood along the indicated diagonal. Find the perimeter and area of the cross section formed by the cut

The perimeter of the cross section formed is 44.22 in.
The area of the cross section formed is 72.44 in.²
From the question, we are to determine the perimeter and area of the cross section formed by the cut
As indicated in the diagram,
If the wood is cut along the indicated diagonal, the cross section formed is a rectangle whose length will be the length of the diagonal and its width will be 4 in.
Now, we will calculate the length of the diagonal,
Let the diagonal be d
Then, we can write that
d² = 2² + 18²
d² = 4 + 324
d² = 328
d = 18.11 in.
Thus,
The length of the rectangular cross-section is 18.11 in.
Now, using the formula for calculating the perimeter of a rectangle
P = 2(l +w)
Where P is the perimeter
l is the length
and w is the width
For the rectangular cross-section
l = 18.11 in.
w = 4 in.
Putting the parameters into the formula,
P = 2(18.11 + 4)
P = 2(22.11)
P = 44.22 in.
∴ The perimeter of the cross section formed is 44.22 in.
For the area of the cross section
Using the formula for calculating the area of a rectangle,
A = l × w
∴ Area of the cross section formed = 18.11 × 4
Area of the cross section formed = 72.44 in.²
Hence, the area of the cross section formed is 72.44 in.²
Learn more on Calculating the area of a rectangle here: https://brainly.com/question/17297081
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