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A mover pushes a 20 kg crate across a level floor with a force of 200 n, but
a the crate accelerates at a rate of only 7.5 m/ s2 because a friction force
opposes the crate's motion. what is the magnitude of this force of friction?
200 n
force of friction
a. 50 n
b. 15 n
c. 25 n
d. 100 n

Respuesta :

onyebuchinnaji

The magnitude of the force of friction between the crate and floor is 50 N.

Magnitude of the force of friction

The magnitude of the force of friction is determined from Newton's second law of motion.

F - Ff = ma

Ff = F - ma

Ff = 200 - (20 x 7.5)

Ff = 50 N

Thus, the magnitude of the force of friction between the crate and floor is 50 N.

Learn more force of friction here: https://brainly.com/question/20241845

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