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What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 n at an angle of 35° above the horizontal? 0.23 m/s2 0.28 m/s2 2.52 m/s2 3.60 m/s2

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Lanuel

Based on the calculations, the acceleration of this wagon along the ground is equal to: D. 3.60 m/s².

Given the following data:

Mass = 10 kg.

Angle = 35°

Force = 44 Newton.

How to calculate the acceleration along the ground?

In accordance with Newton's Second Law of Motion, the net force acting on this wagon is equal to the horizontal component of the force that is parallel to the slope:

F = macosθ

Substituting the given parameters into the formula, we have;

44 = 10 × a × cos35

44 = 10a × 0.8192

44 = 8.192a

a = 44/8.192

a = 3.60 m/s²

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