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Mr. Emmer gave a test in his Chemistry class. The scores were normally distributed with a mean of 82 and a standard deviation of 4. A student is randomly chosen. What is the probability that the student scores a 70 or below? Use the formula for a z-score z = x - mu/infinity where x is the given value, mu is the mean and infinity is the standard deviation. Then refer to the chart on page 11 of the lesson to find the probability. a. .0668.b. .0179.c. .0013.d. .5000.

Respuesta :

MrRoyal

The probability that the student scores a 70 or below is 0.0013

How to determine the probability?

The given parameters are:

  • Mean, μ = 82
  • Standard deviation, σ = 4

The probability that a student scores 70 or below is represented as:

P(x ≤ 70)

Calculate the z score for x = 70 using:

[tex]z =\frac{x - \mu}{\sigma}[/tex]

This gives

[tex]z =\frac{70 - 82}{4}[/tex]

Evaluate

z =-3

The probability becomes

P(x ≤ 70) = P(z ≤ -3)

Using the z tables of probabilities, we have:

P(x ≤ 70) = 0.0013499

Approximate

P(x ≤ 70) = 0.0013

Hence, the probability that the student scores a 70 or below is 0.0013

Read more about probability at:

https://brainly.com/question/251701

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