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A genius IQ is considered anything over 144. Let's pretend that
this is a genetic condition and that it is recessive. Genius IQ
is found in approximately 1 in 625 people worldwide (this is a
true statistic). Calculate the following:
1. The frequency of the recessive allele (genius IQ).
2. The frequency of the dominant allele (normal).
3. The percentage of heterozygous individuals (carriers).

Respuesta :

According to the question, The percentage of heterozygous individuals (carriers). Thus, option "C" is correct.

What is the Hardy-Weinberg equilibrium theory?

The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q. Assuming a diallelic gene,  

p is the frequency of the dominant allele,  

q is the frequency of the recessive allele.

The genotypic frequencies after one generation are  

p² (H0m0zyg0us dominant genotypic frequency),  

2pq (Heter0zyg0us genotypic frequency),  

q² (H0m0zyg0us recessive genotypic frequency)

Thus, option "C" is correct.

To learn more about Hardy-Weinberg equilibrium  click here;

https://brainly.com/question/16823644

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