The total number of different committees that can be made is:
C = 4,536
If we have a set of N elements, the total number of different subsets of K elements that can be made out of these N is:
[tex]C(N, K) = \frac{N!}{(N - K)!*K!}[/tex]
So, the 2 teachers (out of 9) can be selected in:
[tex]C(9, 2) = \frac{9!}{7!*2!} = \frac{9*8}{2} = 36[/tex]
36 different ways.
The 4 students (out of 9) can be selected in:
[tex]C(9, 4) = \frac{9!}{5!*4!} = \frac{9*8*7*6}{4*3*2} = 126[/tex]
126 different ways.
The committee is formed by these two groups, so the total number of different committees that can be made is:
C = 36*126 = 4,536
If you want to learn more about combinations
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