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A sample of air is held in a 722 ml. container at 23.3Β°C. This sample is transferred into a 481 mL container
with a measured pressure of 2.055 atm and a stable temperature of 80.1. What was the initial pressure
in the first container (in atm)?
01.38
0.978
01.24
O 1.15

Respuesta :

Apply combine gas law

  • T1=296.3K
  • T2=353K

So

[tex]\\ \rm\Rrightarrow \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{P1(0.722)}{296.3}=\dfrac{0.481(2.055)}{353}[/tex]

[tex]\\ \rm\Rrightarrow 0.0024P1=0.0028[/tex]

[tex]\\ \rm\Rrightarrow P_1=1.167atm[/tex]

D

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