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Byrn has a stack of photos measuring 12cm wide and 16cm high. He wants to display them on a large rectangular poster in such a way that all photos are equally spaced on each side, including at the edges of the poster, as illustrated (in the attached file)


Q1. Bryn wants to display 9 photos (with longer side vertical) in 3 rows of 3 photos each with 2cm spacing around each photo. What are the dimensions of the poster?


Q2. Bryn wants to display 24 photos (with longer side vertical) with 2cm spacing around each photo. He wants more columns than rows of photos. Find the smallest poster area that is needed.


Q3. Bryn wants to display 18 photos in 3 rows of 6 photos each with 3cm spacing around each photo. The photos may all be displayed in portrait orientation (longer side vertical) or in landscape (longer side horizontal). Which orientation uses the lesser poster area?


Q4. Bryn wants to display 24 photos (with longer side vertical) in 6 rows of 4 photos each with equal spacing around each photo. He has a poster that is 62cm wide and 120cm high. He wants to use the full width of the poster but is prepared to trim some of its height to achieve the equal spacing. How much of the poster does he need to trim?

Please provide working out for all of the answers. Thanks.

Byrn has a stack of photos measuring 12cm wide and 16cm high He wants to display them on a large rectangular poster in such a way that all photos are equally sp class=

Respuesta :

batolisis

The answers for the questions are:

1) The dimensions of poster are 44cm by 56cm

2) The smallest poster area needed is 5328 square centimeter

3) The orientation that uses the lesser poster area is portrait.

4) He needs to trim 4.4cm of the height of poster

What is a rectangle?

A rectangle is a quadrilateral with opposite sides equal and all angles 90°

Analysis:

1) since there are 3 photos per row, the spacing for the three photos are 4. Also since there are 3 photos on the column, the spacing would be 4

 width of poster = 2x4 + 3x12 = 8 + 36 = 44cm

  Height of poster = 4x2 + 3x16 = 56cm

2) possible combinations, are 8 picture on a row and 3 picture on a column

     width = 9spacing x 2cm + 8 pictures x 12 = 114cm

   length = 4 spacing x 2 + 3pictures x 16 = 56cm

   12 pictures on a row and 2 pictures on a column

     width = 13 spacing x 2cm + 12 pictures x 12 = 170cm

      length = 3 spacing x 2cm + 2 pictures x 16 = 38cm

    6 pictures on a row and 4 pictures on a column

      width = 7 spacing x 2cm + 6 pictures x 12 = 72cm

       length = 5 spacing x 2cm + 4 pictures x 16 = 74cm

    The smallest area is 74 x 72 = 5328 square centimeter

3.  For portrait,

     width = 6 photos x 12cm + 7 spacing x 2cm = 86cm

      length = 3 pictures x 16cm + 4 spacing x 2cm = 56cm

     For landscape,

     width = 6 photos x 16cm + 7spacing x 2cm = 110cm

      length = 3 pictures x 12cm + 4 spacing x 2 = 44cm

     The lesser poster area is portrait orientation with 86 x 56 = 4816 square centimeter.

4. Let the equal spacing be P

   for full width = 62cm

    4pictures x 12cm + 5 spacing x P = 62

   48 + 5p = 62

   5P = 62-48

   5P = 14

   P = 14/5 = 2.8cm

   length of poster using equal spacing of 2.8cm

   length would take 6 photos

   6 photos x 16 + 7 spacing x 2.8 = 115.6cm

   original length of poster is 120cm

  so he would need to trim  (120-115.6) = 4.4cm

In conclusion, The answers to the questions are:

1) dimensions of poster are 44cm by 56cm

2) The smallest poster area needed is 5328 square centimeter

3) The orientation that uses the lesser poster area is portrait

4) He needs to trim 4.4cm of the height of poster

Learn more about rectangles: brainly.com/question/25292087

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