The pressure of the given moles of propane with the given volume and temperature is 1.024atm.
The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.
It is expressed as;
PV = nRT
Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )
Given the data in the question;
PV = nRT
P = nRT / V
P = ( 13mol × 0.08206Latm/molK × 288K ) / 300L
P = 307.23264Latm / 300L
P = 1.024atm
Therefore, the pressure of the given moles of propane with the given volume and temperature is 1.024atm.
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