The current flowing in the 4 ohms resistor connected in series with 5-ohm resistor is determined as 1.0 A.
The equivalent resistance of the circuit is determine as follows;
Rt = R1 + R2
Rt = 4 ohms + 5 ohms = 9 ohms
The current flowing in the 4 ohms resistor is determined from Ohms law as shown below;
V = IR
I = V/R
I = 9/9
I = 1.0 A
Since the circuit is in series arrangement, same current will flow in 5 ohm and 4 -ohm.
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