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Different isotopes of the same element emit light at slightly different wavelengths. A wavelength in the emission spectrum of a hydrogen atom is 656.45 nm; for deute- rium, the corresponding wavelength is 656.27 nm. (a) What minimum number of slits is required to resolve these two wavelengths in second order

Respuesta :

okpalawalter8

Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

What minimum number of slits is required to resolve these two wavelengths in second-order?

Generally, the equation for the wave is mathematically given as

[tex]d\ sin\ (\theta\ m) \ = \ m\ \lambda[/tex]

Where the chromatic resolving power (R) is defined by

[tex]R\ =\ \lambda\ / \ d \ \lambda[/tex]

R = nN,

Therefore

[tex]\lambda_1 \ = \ (656.45)(1 \ * \ 10^{-9})/1mm[/tex]

[tex]\lambda_1= 656.45*10^{-9}[/tex]

and

[tex]\lambda_2= (656.27)(1*10^{-9})/1mm[/tex]

[tex]\\\\\lambda_2= 656.27*10^{-9}m[/tex]

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

[tex]N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\[/tex]

Therefore

[tex]N\ =\ \dfrac{656.45 \ * \ 10^{-9}}{2\ * \ (0.18*10^{-9})}[/tex]

N=1820slits

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