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Jacob throws an acorn into the air. It lands in front of him. The acorn's path is
described by the equation y=-3x2 + 6x + 6, where x is the acorn's horizontal
distance from him and y is the height of the acorn.
Solve-3x2 + 6x+6=0 to see where the acorn hits the ground.
Are both solutions reasonable in this situation?

Respuesta :

alexanderorangeguy

Answer:

below

Step-by-step explanation:

-3x² + 6x + 6 = 0

x = (-b±√(b²-4ac))/2a

x = (-6±√(36 - 4(-3)(6)))/2(-3)

x = (-6±√108)/-6

x = 1 ± √3

The negative solution is not reasonable for he threw it forwards

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