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Glauber’s salt, Na2 SO4∙10H2 O(s), was used in the 17 th century as a laxative. Glauber’s salt losses waters of hydration according to the following equilibrium: Na2 SO4∙10H2 O(s) Na2 SO4 (s) + 10 H2 O(g) K = 4.08×10–25 at 25oC What is the partial pressure of water at 25oC in a closed container holding a sample of Glauber’s salt?

I have issue solving this because I don't know what to do for equilibrium constant equation when there is dot for the chemical equation.

Respuesta :

[tex]3.64 X 10^{-3}[/tex] is the partial pressure of water at 25 degrees Celcius in a closed container holding a sample of Glauber’s salt.

What is Glauber's salt?

A colourless crystalline sulfate of sodium [tex]Na_2SO_410H_2O[/tex] is used especially in dyeing, as a cathartic, and in solar energy systems.

Given equation is:

[tex]Na_2SO_410H_2O[/tex] ⇄[tex]Na_2SO_4 + 10H_2O[/tex]

K = [tex]4.08 X 10^{-25}[/tex]at 25 degree celcius.

This equation belongs to a heterogeneous equilibrium.

Reactants and products are not in the same phase.

For heterogeneous equilibrium partial pressure of solids and liquids are

equal to zero and not included in the expression.

Therefore [tex]K_p[/tex] =[tex]P_{H_2O}[/tex]

[tex]4.08 X 10^{-25}[/tex] =[tex]{P_{H_2O}}^{10}[/tex]→ due to coefficient

[tex]P_{H_2O} =3.64 X 10^{-3}[/tex]

Hence, [tex]3.64 X 10^{-3}[/tex] is the partial pressure of water at 25 degrees Celcius in a closed container holding a sample of Glauber’s salt.

Learn more about the  Glauber's salt here:

https://brainly.com/question/7052740

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