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1. A bag contains 40 marbles, 28 red ones and 12 blue ones. A marble is picked at random
from the bag.

What is the probability of picking:
a) a red marble _____
b) a blue marble _____
c) a yellow marble _____​

Respuesta :

semsee45

Answer:

a)  0.7

b)  0.3

c)  0

Step-by-step explanation:

Number of marbles in the bag:

  • 28 red marbles
  • 12 blue marbles

⇒ total marbles = 28 + 12 = 40

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Therefore:

[tex]\implies \sf P(red\:marble)=\dfrac{28}{40}=0.7[/tex]

[tex]\implies \sf P(blue\:marble)=\dfrac{12}{40}=0.3[/tex]

[tex]\implies \sf P(yellow\:marble)=\dfrac{0}{40}=0[/tex]

(As there are no yellow marbles in the bag, the probability of picking a yellow marble is zero)

007Boy

Required Answer :

Given :-

  • A bag contains 40 marbles
  • 28 red ones
  • 12 blue ones
  • A marble is picked at random from bag

To Find :-

  • Probability of picking a) a red marble b) a blue marble c) a yellow marble?

Solution :-

As we clearly know that probability is given by;

  • Probability = (Possible outcomes)/(Total number of outcomes)

a)

  • Probability of a red marble

→ Probability = (No. of red marbles)/(Total marbles)

→ Probability = 28/40

→ Probability = 0.7

b)

  • Probability of a blue marble

→ Probability = (No. of blue marbles)/(Total marbles)

→ Probability = 12/40

→ Probability = 0.3

c)

  • Probability of a yellow marble

→ Probability = (No. of yellow marbles)/(Total marbles)

→ Probability = 0/40

→ Probability = 0

Hence, solved!

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