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Using indefinite integration. Calculate the following integrals.

A) dy/dx = 0.5 sin(3x) + 5cos(10x)

B) dy/dx = 12e^4x

C) dy/dx = 0.5x + 6x^2

Respuesta :

evgeniylevi

Step-by-step explanation:

[tex]A) \ y=\int\ ({0.5sin3x+5cos10x}) \, dx=0.5sin10x-\frac{1}{6}cos3x+C;[/tex]

[tex]B) \ y=\int\ {12e^{4x}} \, dx=3e^{4x}+C;[/tex]

[tex]C) \ y=\int\ {0.5x+6x^2} \, dx=0.25x^2+2x^3+C;[/tex]

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