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[tex]\leadsto\mid\boldsymbol{-Answer-}\mid\gets[/tex]

Distance =

[tex]\leadsto\mid\boldsymbol{-Explanation-}\mid\gets[/tex]

Use the distance formula, which is.

[tex]\sf d=\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

Plug in the values.

[tex]\sf d=\sqrt{(4-2)^2 +(5-3)^2[/tex]

Simplify.

[tex]\sf d=\sqrt{2^2+2^2}[/tex]

Simplify.

[tex]\sf d=\sqrt{8}[/tex].

Decimal Form. 2.828427...

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Answer:

Distance = 2√2 units

Step-by-step explanation:

Distance = ?

Solution:

Use distance's formulae:

[tex] \rm \: D =\sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}[/tex]

  • [tex]\rm (x_2,x_1) = (4,2)[/tex]
  • [tex]\rm (y_2,y_1) = (5,3)[/tex]

Substituting them,we obtain

  • [tex] \rm \: D = \sqrt{(4 - 2) {}^{2} + (5 - 3) {}^{2} }[/tex]
  • [tex]\rm D = \sqrt{2 {}^{2} + 2 {}^{2} } [/tex]
  • [tex]\rm D = \sqrt{4 + 4} [/tex]
  • [tex]\rm D = \sqrt{8} [/tex]
  • [tex]\boxed{\rm D =2 \sqrt{2} \; units} [/tex]

Hence,the distance is 2√2 units.