Respuesta :

Using the normal distribution, looking at the z-table, it is found that the value of c is of c = -0.95.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

For the standard normal distribution, we have that P(Z > c) = 0.8292 for c that has a p-value of 1 - 0.8292 = 0.1708, hence the value is of c = -0.95.

More can be learned about the normal distribution at https://brainly.com/question/25800303

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