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Suppose you have a container of liquid that has equilibrated with the air above its surface, such the PO2 in the liquid is approximately 160 mm Hg. You then very rapidly exchange the gas above the liquid for a new gas that has a total pressure of 1520 mm Hg (twice atmospheric pressure) and a PO2 of 160 mm Hg. What is the PO2 in the liquid immediately after the switch and one hour after the switch?

Respuesta :

160 mmHg is the [tex]PO_2[/tex] in the liquid immediately after the switch and one hour after the switch.

What is atmospheric pressure?

It is the force exerted on a surface by the air above it as gravity pulls it to Earth.

Since air contains 20.95% [tex]O_2[/tex].

So the pressure of [tex]O_2[/tex] just after switching

[tex]=\frac{1520 X 20.95}{100} mm Hg[/tex]

=15.20 X 20.95 mm Hg

=318.44 mm Hg

After one hour since [tex]O_2[/tex] in air and liquid will attain equilibrium.

So, the final pressure of [tex]O_2[/tex] will be the equilibrium of [tex]PO_2[/tex] is 160 mmHg.

Learn more about the atmospheric pressure here:

https://brainly.in/question/7639472

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