Respuesta :
Hence, 1.64x[tex]10^{7}[/tex] lbft work it takes to pump the kerosene to the level 4 ft above the top of the tank.
Given, that the height of the cylinder = 30 ft, the diameter of the cylinder = 20 ft and the weight of the kerosene = 51.2 lb/ft³
Radius of the cylinder = d/2=20/2=10 ft
We need to calculate how much work it takes to pump the kerosene to the level of the top of the tank.
We know that the volume of the cylinder = V = πr²h
⇒V= 3.14×10²×30 ft³
⇒V=9424.8 ft³
Weight of kerosene=51.2 Ib/ft³×9424.8 ft³ = 482548.6 lb
Work done to pump kerosene 4ft above the cylinder
= weight×height=482548.6×(30+4)ft=1.64x[tex]10^{7}[/tex] lbft
Hence, 1.64x[tex]10^{7}[/tex] lbft work it takes to pump the kerosene to the level 4 ft above the top of the tank.
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