9.3189 grams of KCl are required to prepare 500.0 mL of a 0.250 M solution.
Define the molarity of a solution.
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.
Given data:
Molarity of the solution = 0.250 M
Volume of solution = 500.0 mL = 0.5 L
Moles =?
[tex]Molarity = \frac{Moles \;solute}{ Volume \;of \;solution \;in \;litre}[/tex]
[tex]0.250 M = \frac{Moles \;solute}{ 0.5 L}[/tex]
0.125 = Moles
[tex]Mole = \frac{mass}{molar \;mass}[/tex]
[tex]0.125 = \frac{mass}{molar \;mass}[/tex]
[tex]0.5 = \frac{mass}{74.5513 g/mol}[/tex]
9.3189 g = Mass
Hence, 9.3189 grams of KCl are required to prepare 500.0 mL of a 0.250 M solution.
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