In a large population, 55% of the people have been vaccinated. if 5 people are randomly selected, what is
the probability that at least one of them has been vaccinated?
give your answer as a decimal to 4 places.

Respuesta :

Using the binomial distribution, it is found that there is a 0.9815 = 98.15% probability that at least one of them has been vaccinated.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, the values of the parameters are:

n = 5, p = 0.55

The probability that at least one of them has been vaccinated is given by:

[tex]P(X \leq 1) = 1 - P(X = 0)[/tex]

In which:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{5,0}.(0.55)^{0}.(0,45)^{5} = 0.0185[/tex]

Then:

[tex]P(X \leq 1) = 1 - P(X = 0) = 1 - 0.0185 = 0.9815[/tex]

0.9815 = 98.15% probability that at least one of them has been vaccinated.

More can be learned about the binomial distribution at https://brainly.com/question/24863377

#SPJ1