If the first inequality is written as:
3x ≤ -12
Then the correct option is D.
If it is written as it is in the problem, then neither of the graphs is the correct option.
How to solve the compound inequality?
Here we have the inequalities:
3x ≤ 12
2x + 3 > 11
(notice that in all the options, the first inequality has a negative sign, while in the two given inequalities there are no negative sign. This means that you will never get the correct answer if you use the given information, as the problem is incorrectly written).
First, we need to isolate x on both inequalities, we will get:
3x ≤ 12
x ≤ 12/3
x ≤ 4
(As you can see, because we don't have the negative sign, this inequality is different to all the ones in the options).
And for the other:
2x + 3 > 11
2x > 11 - 3
x > 8/2
x > 4
So neither of the options is actually correct.
If we instead write the first inequality as:
3x ≤ -12
We would solve this as:
x ≤ -4
And in that case, our two inequalities are:
x ≤ -4
x > 4
So the correct graph is graph D.
If you want to learn more about inequalities:
https://brainly.com/question/18881247
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