contestada

Which equation is the inverse of y = 16x² +1?
X
O Y=√16
O Y= 16
-1
0 У.
О У.
y=√x -1
±√√x-1
4

Respuesta :

tmarsheuna63

Answer:

[tex]x = + - \sqrt{ \frac{y - 1}{16} } [/tex]

Step-by-step explanation:

[tex]y - 1 = 16 {x}^{2} \\ \frac{y - 1}{16} = {x}^{2} \\ + - \sqrt{ \frac{y - 1}{16} } = {x} \\ x = + - \sqrt{ \frac{y - 1}{16} } [/tex]

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