1). Option C
2). Option A
Polygon is given as a closed two-dimensional figure with three or more straight lines.
The given vertices of polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8) and E(6, 6)
After reflection new polygon formed MNOPQ has the vertices M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8) and Q(-6, 6).
By comparing the vertices we find the x-coordinates of polygon ABCDE have been changed to MNOPQ by negative notation only. Y- coordinates are same.
Therefore, polygon ABCDE has been reflected across the y-axis.
Option C. is the answer.
If polygon MNOPQ is translated 3 units right and 5 units down then the new vertices of congruent polygon VWXYZ will be
M(-2, 8) = [(-2 - 3), (8 + 5)] = (-5, 13)
N(-4, 12) = [(-4 - 3), (12 + 5)] = (-7, 17)
O(-10, 12) = [(-10 - 3),(12 + 5)] = (-13, 17)
P(-8, 8) = [(-8 - 3), (8 + 5)] = (-11, 13)
Q(-6, 6) = [(-6 -3),(6 + 5)] = (-9, 11)
Thus, Option A. is the correct option.
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