Respuesta :
Using the Poisson distribution, it is found that:
- The probability of 15 patients in a day is of 0.0992.
- In a month, the mean number of days with 15 patients is of 2.976.
What is the Poisson distribution?
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
- x is the number of successes
- e = 2.71828 is the Euler number
- [tex]\mu[/tex] is the mean in the given interval.
In this problem, the mean is of [tex]\mu = 16[/tex], hence the probability of 15 patients in a day is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 15) = \frac{e^{-16}16^{15}}{(15)!} = 0.0992[/tex]
Hence the mean number of days in a month (30 days) with 15 patients visiting is given by:
M = 30 x 0.0992 = 2.976.
More can be learned about the Poisson distribution at https://brainly.com/question/13971530
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