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The diagonals of parallelogram abcd intersect at point e. to prove that bae= dce, all of the following could be used, except for which

a.the sum of measures of the interior angles of abcd is 360 degrees
b. abc = cda by sss
c. abc = cde by sss
d. given two parallel lines by transversal, alternates interior angles are congruent.

Respuesta :

The only option that cannot be used to prove that the diagonals of parallelogram abcd intersect at point e is; Option C

How to determine quadrilateral proof?

A) The sum of the interior angles of any quadrilateral is 360° and so this is true about the parallelogram.

B) AB = CD and BC = DA from opposite sides of a parallelogram are equal. Also AC = CA because of reflexive property of congruence. Thus, ∠ABC ≅ ∠CDA

C) This is not true because ∠ABC ≅ ∠CDA instead of ∠ABC ≅ ∠CDE.

D) This is true because of the definition of a transversal.

Read more about proof of quadrilateral at; https://brainly.com/question/27846700

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