The attached image represents the foci of the hyperbola
How to determine the foci?
The equation of the hyperbola is given as:
[tex]\frac{x^2}{625} - \frac{y^2}{3600} = 1[/tex]
Rewrite as:
[tex]\frac{x^2}{25^2} - \frac{y^2}{60^2} = 1[/tex]
A hyperbola is represented as:
[tex]\frac{(x - h)^2}{b^2} - \frac{(y - k)^2}{a^2} = 1[/tex]
This means that:
h = 0
k = 0
b = 25
a = 60
Next, calculate c the distance from the center to the focus using:
[tex]c = \sqrt{a^2 -b^2}[/tex]
This gives
[tex]c = \sqrt{60^2 -25^2}[/tex]
Evaluate
[tex]c = \pm \sqrt{2975}[/tex]
This means that:
Foci = (0, -√2975) and (0, √2975)
See attachment for the hyperbola and the foci
Read more about hyperbola at:
https://brainly.com/question/16735067
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