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A climber throws a rope with a velocity of 3.0 m/s downward to another climber 4.0 m directly below. Conclude the rope’s velocity when it reached the lower climber? Assume no air resistance and that a = -g = -9.81 m/s2.

Respuesta :

The rope’s velocity when it reached the lower climber is 9.35 m/s.

What is gravity?

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given is a climber throws a rope with a velocity of 3.0 m/s downward to another climber 4.0 m directly below

The upward acceleration is equal to the acceleration due to gravity a = -g = -9.81 m/s

Using the third equation of motion ,we have

Vf² -Vi² =2as

Put the values, we get

Vf² = 3² + 2(-4.0)(-9.81)

Vf = 9.35 m/s

Thus, rope’s velocity when it reached the lower climber is 9.35 m/s.

Learn more about gravity.

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