You are driving through town at 11.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.2 m/s?

You are driving through town at 110 ms when suddenly a ball rolls out in front of you You apply the brakes and begin decelerating at 32 ms class=
You are driving through town at 110 ms when suddenly a ball rolls out in front of you You apply the brakes and begin decelerating at 32 ms class=

Respuesta :

The distance moved by the vehicle on after brakes is 18.91 m.

What is speed?

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Speed s = distance d / time t

You are driving through town at 11.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.2 m/s.

The final velocity will be zero, when brakes are applied.

Using the third equation of motion,

v² -u² =2as

0² - 11² = 2x (-3.2) s

s = 18.91 m

Thus, the distance moves on applying brakes, is  18.91 m.

When half of the distance is traveled, the speed will be

v² -u² =2as

0² - u² = 2x (-3.2) (18.91/2)

u = 7.78 m/s

Thus, the speed will be 7.78 m/s i.e greater than 5.5 m/s.

Learn more about speed.

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