The equation of the line perpendicular ton the given line is y = -3x +6
A equation of a straight line is given by
y = mx+c ,
where m is the slope and c is the intercept on y axis.
The given line is
y = (1/3)x +4
The slope is 1/3
Te slope of the line perpendicular to a line is given by
m * m' = -1
(1/3) * m' = -1
m' = -3
The equation of the line is
y = -3x + c
The x intercept is 2
At y = 0, x =2
0 = -6 +c
c =6
Therefore the equation of the line perpendicular ton the given line is
y = -3x +6
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