At 298 K, AH = 46 kJ/mol and Sº = 0.097 kJ/(K-mol). What is the Gibbs
free energy of the reaction?
A. 75 kJ
B. 1300 kJ
C. 0.63 kJ
D. 17 kJ

Respuesta :

Answer:

The Gibbs free energy for the reaction is 17 kJ.

Explanation:

The Gibbs free energy at STP is given as:

ΔG°=ΔH°-TΔS°

We have been given:

ΔH°=46 kJ/mol

ΔS°=0.097 kJ/K-mol

T=298 K

Putting these values in equation,we get:

ΔG°=46 - 298.(0.097) kJ

ΔG°=46 - 28.906 kJ

ΔG°=17.094 kJ

ΔG°≈ 17 kJ

GIBBS FREE ENERGY IS DEFINED AS:

" The Gibbs free energy is a thermodynamic potential that can be used to calculate the maximum amount of work that may be performed by a thermodynamically closed system at constant temperature and pressure. It also provides a necessary condition for processes such as chemical reactions that may occur under these conditions."

To learn more about GIBBS FREE ENERGY refer to:

https://brainly.com/question/9179942

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