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In the diagram, DG = 15, GF = 5, EH = 12, and DE = 8.

Triangle D F E is shown. Line segment G H is drawn from side D F to side E F to form triangle G F H. The length of D G is 15, the length of G F is 5, the length of E H is 12, and the length of D E is 8.

To prove that â–³DFE ~ â–³GFH by the SSS similarity theorem using the information provided in the diagram, it would be enough additional information to know that

Respuesta :

To prove that â–³DFE ~ â–³GFH by the SSS similarity theorem, the correct answer is; Option C: HF is 4 units and GH is 2 units

How to prove the similarity theorem?

The SSS Similarity theorem states that two triangles are similar If all the three sides of one of the triangles are in same proportion to the three sides of the other triangle.

Since triangle DFE is similar to triangle GHF as seen in the attached diagram, then we can say that;

DF/GF = DE/GH

20/5 = 8/GH

GH = 2 units

Also:

EF/HF = DF/GF

(12 + HF)/HF = 20/5

HF = 4 units

Read more about Similarity Theorem at; https://brainly.com/question/21247688

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