Answer:
Step-by-step explanation:
(-4,8) ; x₁ = -4 & y₁ = 8
(7,-6) ; x₂ = 7 & y₂ = -6
[tex]\sf \boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf =\dfrac{-6-8}{7-[-4]}\\\\ =\dfrac{-14}{7+4}\\\\=\dfrac{-14}{11}[/tex]
Equation of line:
[tex]\sf y-y_1=m(x-x_1)[/tex]
[tex]y - 8 = \dfrac{-14}{11}(x -[-4])\\\\y- 8 = \dfrac{-14}{11}(x+4)\\\\y -8 = \dfrac{-14}{11}x-\dfrac{14*4}{11}\\\\ y = \dfrac{-14}{11}x-\dfrac{56}{11}+8\\\\ y =\dfrac{-14}{11}x-\dfrac{56}{11}+\dfrac{88}{11}\\\\y=\dfrac{-14}{11}x+\dfrac{32}{11}[/tex]
