The value of k is 4 and the value of a is 5
How to determine the value of k?
The table of values is given as:
x=2,3,a
y=20,40,104
The variation is given as:
[tex]y\ \alpha\ x^2+1[/tex]
Express as an equation
y = k(x^2 + 1)
When x = 2, y = 20.
So, we have:
[tex]20 = k(2^2 + 1)[/tex]
Evaluate the sum
20 = 5k
Divide by 5
k = 4
Hence, the value of k is 4
How to determine the value of a?
In (a), we have:
y = k(x^2 + 1)
Substitute 4 for k
y = 4(x^2 + 1)
When x = a, y = 104.
So, we have:
104 = 4(a^2 + 1)
Divide by 4
26 = a^2 + 1
Subtract 1 from both sides
a^2 = 25
Take the square root
a = 5
Hence, the value of a is 5
Read more about direct variation at:
https://brainly.com/question/6499629
#SPJ1
