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Sulfuric acid is an important industrial chemical that
is usually produced by a series of reactions. One of
these involves an equilibrium between gaseous sulfur
dioxide, oxygen, and sulfur trioxide.
2 SO₂(g) + O₂(g) 2 SO₂(g)
If 2.5 mol of sulfur dioxide gas and 2.0 mol of
oxygen gas are placed in a sealed 1.0 L container
and allowed to reach equilibrium, 0.75 mol of sulfur
dioxide remains. Use an ICE table to determine the
concentration of the other gases at equilibrium.

Respuesta :

The concentration of sulphur dioxide = 0.75 mol/litre, The concentration of Oxygen is 1.125 mol/litre, The concentration of sulphur trioxide is 1.75 mol/l.

What is a Balanced Equation ?

A equation in which the atoms of each element in the reactants and the products are same is called Balanced Equation .

The equation given is

2 SO₂(g) + O₂(g) 2 SO₃(g)

The initial moles of sulphur dioxide gas = 2.5 mol.

Initial Moles of Oxygen is 2 moles

The moles of sulphur dioxide gas at equilibrium is 0.75 mol

The mole ratio of sulphur dioxide to oxygen is 2:1

The mole ratio of sulphur dioxide to sulphur trioxide is 1 :1

The used up moles of sulphur dioxide is

2.5 - 0.75 = 1.75 mol

The oxygen required by 1.75 mole is 0.875 mol

The oxygen at equilibrium will be

2 -0.875

1.125 mol

The sulphur trioxide formed from 1.75 mol of sulphur dioxide at the equilibrium will be 1.75 mol.

Concentration = moles / Volume

Volume = 1L

Therefore the concentration of sulphur dioxide = 0.75 mol/litre

The concentration of Oxygen is 1.125 mol/litre

The concentration of sulphur trioxide is 1.75 mol/l.

To know more about a Balanced Equation

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