Respuesta :

fieryanswererft

Answer:

[tex]\boxed{\sf x = \dfrac{1}{21}}[/tex]

Explanation:

[tex]\rightarrow \sf 3x+7-6= \dfrac{8}{7} - 0[/tex]

simplify the following

[tex]\rightarrow \sf 3x+1= \dfrac{8}{7}[/tex]

subtract 1 from both sides

[tex]\rightarrow \sf 3x+ 1 -1= \dfrac{8}{7} - 1[/tex]

simplify the following

[tex]\rightarrow \sf 3x= \dfrac{1}{7}[/tex]

multiply both sides by 1/3

[tex]\rightarrow \sf 3x \cdot \dfrac{1}{3}= \dfrac{1}{7}\cdot \dfrac{1}{3}[/tex]

simplify the following

[tex]\rightarrow \sf x = \dfrac{1}{21}[/tex]

juwairiyah53

[tex]3x + 7 - 6 = \frac{8}{7} - 0 \\ \\ 3x + 1 = \frac{8}{7} \\ \\ 3x = \frac{8}{7} - 1 \\ \\ 3x = \frac{ 8 - 7}{7} \\ \\ 3x = \frac{1}{7} \\ \\ x = \frac{1}{7 \times 3} \\ \\ x = \frac{1}{21} .[/tex]

Otras preguntas