The local public pool is a rectangle with two semicircles.


The area of the rectangle is
.



Using 3.14 for π and rounding to the nearest meter, the area of each half circle is
m2.



The area of the surface of the pool is
m2.

Respuesta :

The area of the surface of the pool is 7322.64 m².

What is Area of rectangle?

The area of rectangle is product of length and its breadth.

i.e., length * breadth

Given: Length = 100 m, Width = 52 m and Diameter = 52 m

Area of rectangle,

= 100 × 52

= 5200 m²

Now,

Area of semicircle = 1/2 × πr²

=1/2 × 3.14 × 26²

= 1061.32 m²

Hence, area of the surface of the pool is

= 1061.32 + 1061.32 + 5200

= 7322.64 m²

Learn more about this concept here:

https://brainly.com/question/15461609

#SPJ1