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An ice cube is freezing in such a way that the side length s, in inches, is s(t)=1/2t+4, where it is in hours. The surface area of the ice cube is the function A(s) = 6s²_
Part A: Write an equation that gives the volume at t hours after freezing begins. (2 points)

Part B: Find the surface area as a function of time, using composition, and determine its range. (4 points)

Part C: After how many hours will the surface area equal 294 square inches? Show all necessary calculations. (4 points)

Help Please!!

An ice cube is freezing in such a way that the side length s in inches is st12t4 where it is in hours The surface area of the ice cube is the function As 6s Par class=

Respuesta :

The equation of volume will be V = [(1/2)t + 4]³. The surface area as a function of time will be A(s) = 3/2 t² + 24t + 96. The number of hours when the surface area equal 294 square inches will be 3 1/2 hours.

What is a function?

Functions are found all across mathematics and are required for the creation of complex relationships.

Part A: The equation that gives the volume at t hours after freezing begins will be

V = s³

V = [(1/2)t + 4]³

Part B: The surface area as a function of time, using composition, and determine its range will be

A(s) = 6(1/2 t + 4)²

A(s) = 6 (t²/4 + 4t + 16)

A(s) = 3/2 t² + 24t + 96

Part C: The number of hours when the surface area equal 294 square inches will be

294 = 6(1/2 t + 4)²

49 = (1/2 t + 4)²

7 = 1/2 t + 4

1/2 t = 3

t = 3 1/2 hours

More about the function link is given below.

https://brainly.com/question/5245372

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