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Line AB and Line CD bisect each other at point E. If AE = 3x - 10y + 123, BE = -2x - 7y + 122, CE = 9x + 10y - 171, and DE = 3x + 20y - 249, what are the values of x and y?

Respuesta :

The values of x and y are 7 and 12 respectively

Solving simultaneous equations

From the question, we are to determine the values of x and y

From the given information,

Line AB and Line CD bisect each other at point E

Then, we can conclude that

AE = BE

and

CE = DE

From the given information,

AE = 3x - 10y + 123

BE = -2x - 7y + 122

CE = 9x + 10y - 171

DE = 3x + 20y - 249

Then, we can write that

3x - 10y + 123 = -2x - 7y + 122

Simplifying

3x +2x -10y + 7y = 122 -123

5x -3y = -1 ----------- (1)


Also,

9x + 10y - 171 = 3x + 20y - 249

Simplifying

9x -3x +10y -20y = -249 + 171

6x -10y = -78 --------- (2)

Now, solve equations (1) and (2) simultaneously

5x -3y = -1 ----------- (1)

6x -10y = -78 --------- (2)

Multiply equation (1) by 10 and equation (2) by 3

10 × ( 5x -3y = -1

3 × ( 6x -10y = -78

50x -30y = -10 ----------- (3)

18x -30y = -234--------- (4)

Then, subtracting equation (4) from equation (3), we get

50x -18x -30y-(-30y) = -10-(-234)

32x -30y + 30y = -10 + 234

32x = 224

∴ x = 224/32

x = 7

Put the value of x into equation (1), to find y

5x -3y = -1

5(7) -3y = -1

35 -3y = -1

35 + 1 = 3y

36 = 3y

∴ y = 36/3

y = 12

Hence, the values of x and y are 7 and 12 respectively

Learn more on Solving simultaneous equations here: https://brainly.com/question/148035

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